• 时事博文
  • 文化时尚
  • 潮流娱乐
  • 生活常识
  • 健康生活
  • 旅游攻略
  • 体育风云
  • 财经博文
  • 汽车频道
  • 科技
  • 游戏
  • 女人
  • 互联网
  • 军事博览
  • 个性推荐
  • 当前位置: 精彩博文网 > 科技 > 正文

    SQL高级查询 oracle菜鸟教程

    时间:2018-08-15 16:29:48 来源:精彩博文网 本文已影响 精彩博文网手机站

    t_tudent(sid,sname,sage,ssex,sdept) 学生表

    t_course(cid,cname,tid) 课程表

    t_score( scid,sid,cid,grade) 成绩表

    t_teacher(tid,tname) 教师表

    问题:

    1、查询“001”课程比“002”课程成绩高的所有学生的学号;

    select t1.sid from

    (select sid,grade from t_score where cid = "001") t1,

    (select sid,grade from t_score where cid = "002") t2

    where t1.grade >t2.grade and t1.sid = t2.sid;

    select t2.sid,t2.ca,t2.cb(

    select t1.sid,sum(t1.ca) ca,sum(t1.cb) cb

    from

    (

    select sid,

    CASE WHEN cid = "001" THEN grade ELSE 0 END ca,

    CASE WHEN cid = "002" THEN grade ELSE 0 END cb

    from t_score

    )t1

    GROUP BY sid

    )t2

    where t2.ca > t2.cb

    2、查询平均成绩大于60分的同学的学号和平均成绩;

    select sid,avg(grade ) from t_score

    group by sid

    having avg(grade ) >60;

    3、查询所有同学的学号、姓名、选课数、总成绩;

    select t1.sid,t1.sname,count(t2.cid),sum(grade ) from t_student t1

    left join t_score t2

    on t1.sid = t2sid

    group by t1sid,t1.sname;

    4、查询姓“李”的老师的个数;

    select count(distinct(tname)) from t_teacher where tname like "李%";

    5、查询没学过“叶平”老师课的同学的学号、姓名;

    select sid, sname from t_student

    where sid not in

    (

    select distinct(t1.sid) from t_score t1,t_course t2,t_teacher t3

    where t1.cid = t2.cid and t3.tid = t2.tid and t3.tname = "叶平"

    );

    6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;

    select t0.sid,t0.sname from t_student t0, t_score t1

    where t0.sid = t1.sid and t1.cid = "001"

    and exists

    (

    select * from t_score t2 where t2.sid = t1.sid and t2.cid = "002"

    );

    7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;

    select sid,sname from t_student

    where sid in

    (

    select sid from t_score t1 ,t_course t2,t_teacher t3

    where t1.cid=t2.cid

    and t3.tid=t2.tid

    and t3.tname = "叶平"

    group by sid

    having count(t1.cid)=(

    select count(cid) from t_course t1,t_teacher t2

    where t2.tid=t1.tid and t2.tname = "叶平"

    )

    );

    8、查询“001”课程比“002”课程成绩高的所有同学的学号、姓名;

    Select sid,sname from

    (

    select t1.sid,t1.sname,t2.grade ,

    (

    select grade from t_score t3

    where t3.sid = t1.sid and t3.cid = "002"

    ) grade2

    from t_student t1, t_score t2

    where t1sid = t2.sid and t2.cid = "001"

    ) S_2

    where grade 2 < grade ;

    9、查询所有课程成绩小于60分的同学的学号、姓名;

    select sid,sname from t_student

    where sid not in

    (

    select t1.sid from t_student t1, t_score t2

    where t1.sid = t2.sid and t2.grade >60

    );

    10、查询没有学全所有课的同学的学号、姓名;

    select t1.sid,t1.sname from Student t1, t_score t2

    where t1.sid = t2.sid

    group by t1.sid,t1.sname

    having count(t2.cid) < (select count(cid) from t_course);

    11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名;

    select sid,sname from t_student t1, t_score t2

    where t1.sid = t2.sid

    and cid in (select cid from t_score where sid = "1001");

    12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;

    select distinct t2.sid,t1.sname from t_student t1, t_score t2

    where t1.sid = t2.sid

    and cid in (select cid from t_score where sid = "001");

    13、把“ t_score”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;

    update t_score t4 set grade =(select avg( t3.grade ) from t_score t3 where t3.cid= t4.cid )

    from t_course t1,t_teacher t2

    where t1.cid = t4.cid

    and t1.tid = t2.tid

    and t2.tname = "叶平");

    14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名;

    select sid from t_score

    where cid in (select cid from t_score where sid = "1002")

    group by sid

    having count(*)=(select count(*) from t_score where sid = "1002");

    15、删除学习“叶平”老师课的 t_score表记录;

    delect t_score from t_course t1 ,t_teacher t2

    Where t1.cid = t2.cid

    and t1.tid = t2.tid

    and t2.tname = "叶平";

    16、向 t_score表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、

    号课的平均成绩;

    insert t_score

    select sid,"002",(Select avg(grade ) from t_score where cid = "002")

    from t_student

    where sid not in (Select sid from t_score where cid = "002");

    17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分

    SELECT sid as 学生ID,

    (SELECT grade FROM t_score WHERE sid=t.sid AND cid="004") AS 数据库,

    (SELECT grade FROM t_score WHERE sid=t.sid AND cid="001") AS 企业管理,

    (SELECT grade FROM t_score WHERE sid=t.sid AND cid="006") AS 英语,

    COUNT(*) AS 有效课程数,

    AVG(t.grade ) AS 平均成绩

    FROM t_score AS t

    GROUP BY sid

    ORDER BY avg(t.grade )

    18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分

    SELECT t1.cid As 课程ID,t1.grade AS 最高分,t2.grade AS 最低分

    FROM t_score t1 , t_score t2

    WHERE t1.cid = t2.cid

    and t1.grade = (

    SELECT MAX(tt1.grade ) FROM t_score tt1,t_student tt2

    WHERE t1.cid = tt1.cid and tt2.sid = tt1.sid

    GROUP BY tt1.cid

    )

    AND t2.grade = (

    SELECT MIN(tt3.grade ) FROM t_score AS tt3

    WHERE t2.cid = tt3.cid GROUP BY tt2.cid

    );

    19、按各科平均成绩从低到高和及格率的百分数从高到低顺序

    SELECT t.cid AS 课程号,max(ame)AS 课程名,isnull(AVG(grade ),0) AS 平均成绩 ,

    100 * SUM(CASE WHEN isnull(grade ,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数

    FROM t_score t1,t_course t2

    where t1.cid = t2.cid

    GROUP BY t1.cid

    ORDER BY 100 * SUM(CASE WHEN isnull(grade ,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

    20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004)

    SELECT

    SUM(

    CASE WHEN cid = "001"

    THEN grade ELSE 0 END)/SUM(CASE cid WHEN "001"

    THEN 1 ELSE 0 END

    ) AS 企业管理平均分 ,

    100 * SUM(

    CASE WHEN cid = "001" AND grade >= 60

    THEN 1 ELSE 0 END)/SUM(CASE WHEN cid = "001"

    THEN 1 ELSE 0 END

    ) AS 企业管理及格百分数 FROM t_score

    21、查询不同老师所教不同课程平均分从高到低显示

    SELECT max(t3.tid) AS 教师ID,MAX(t3.tname) AS 教师姓名,

    T2.cid AS 课程ID,MAX(ame) AS 课程名称,AVG(grade ) AS 平均成绩

    FROM t_score AS t1,t_course AS t2 ,t_teacher AS t3

    where t1.cid = t2.cid and t2.tid = t3.tid

    GROUP BY t2.cid

    ORDER BY AVG(grade ) DESC ;

    22、查询如下课程成绩第 3 名到第 6 名的学生成绩单:企业管理(001),马克思(002),UML (003),数据库(004)

    [学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩

    SELECT DISTINCT top 3 t_score.sid As 学生学号,Student.Sname AS 学生姓名 ,

    T1.grade AS 企业管理, T2.grade AS 马克思, T3.grade AS UML,

    T4.grade AS 数据库,ISNULL(T1.grade ,0) + ISNULL(T2.grade ,0) + ISNULL(T3.grade ,0) + ISNULL(T4.grade ,0) as 总分

    FROM Student, t_score

    LEFT JOIN t_score AS T1

    ON t_score.sid = T1.sid AND T1.cid = "001"

    LEFT JOIN t_score AS T2

    ON t_score.sid = T2.sid AND T2.cid = "002"

    LEFT JOIN t_score AS T3

    ON t_score.sid = T3.sid AND T3.cid = "003"

    LEFT JOIN t_score AS T4

    ON t_score.sid = T4.sid AND T4.cid = "004"

    WHERE student.sid= t_score.sid

    and ISNULL(T1.grade ,0) + ISNULL(T2.grade ,0) + ISNULL(T3.grade ,0) + ISNULL(T4.grade ,0)

    NOT IN (

    SELECT DISTINCT TOP 15 WITH TIES ISNULL(T1.grade ,0) + ISNULL(T2.grade ,0) + ISNULL(T3.grade ,0) + ISNULL(T4.grade ,0)

    FROM t_score

    LEFT JOIN t_score AS T1

    ON t_score.sid = T1.sid AND T1.cid = "k1"

    LEFT JOIN t_score AS T2

    ON t_score.sid = T2.sid AND T2.cid = "k2"

    LEFT JOIN t_score AS T3

    ON t_score.sid = T3.sid AND T3.cid = "k3"

    LEFT JOIN t_score AS T4

    ON t_score.sid = T4.sid AND T4.cid = "k4"

    ORDER BY ISNULL(T1.grade ,0) + ISNULL(T2.grade ,0) + ISNULL(T3.grade ,0) + ISNULL(T4.grade ,0) DE t_score

    );

    23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]

    SELECT t1.cid as 课程ID, ame as 课程名称,

    SUM(CASE WHEN t1.grade BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85],

    SUM(CASE WHEN t1.grade BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70],

    SUM(CASE WHEN t1.grade BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60],

    SUM(CASE WHEN t1.grade < 60 THEN 1 ELSE 0 END) AS [60 -]

    FROM t_score t1,t_course t2 where t1.cid = t2.cid

    GROUP BY t1.cid,ame;

    24、查询学生平均成绩及其名次

    SELECT

    1+(

    SELECT COUNT( distinct avggrade )

    FROM (

    SELECT sid,AVG(grade ) AS avggrade FROM t_score GROUP BY sid

    ) AS T1 WHERE avggrade > T2.avggrade ) as 名次,

    sid as 学生学号,

    avggrade

    FROM (

    SELECT sid,AVG(grade )as avggrade FROM t_score GROUP BY sid

    ) AS T2

    ORDER BY avggrade desc;

    25、查询各科成绩前三名的记录:(不考虑成绩并列情况)

    SELECT t1.sid as 学生ID,t1.cid as 课程ID,grade as 分数

    FROM t_score t1 WHERE grade IN (

    SELECT TOP 3 grade FROM t_score t2 WHERE t1.cid = t2.cid ORDER BY grade DESC

    )

    ORDER BY t1.cid;

    26、查询每门课程被选修的学生数

    select cid,count(sid) from t_score group by cid;

    27、查询出只选修了一门课程的全部学生的学号和姓名

    select t1.sid,t2.sname,count(t1.cid) AS 选课数 from t_score t1,t_student t2

    where t1.sid=t2.sid

    group by t1.sid ,t2.sname

    having count(t1.cid)=1;

    28、查询男生、女生人数

    Select count(ssex) as 男生人数 from t_student group by ssex having ssex="男";

    Select count(ssex) as 女生人数 from t_student group by ssex having ssex="女";

    29、查询姓“张”的学生名单

    SELECT sname FROM t_student WHERE sname like "张%";

    30、查询同名同性学生名单,并统计同名人数

    select sname,count(*) from t-student group by sname having count(*)>1;

    31、1981年出生的学生名单(注:Student表中Sage列的类型是datetime)

    select sname, CONVERT(char(11),DATEPART(year,sage)) as age

    from t_tudent

    where CONVERT(char(11),DATEPART(year,Sage))="1981";

    32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列

    Select cid,Avg(grade ) from t_score group by cid order by Avg(grade ),cid DESC

    33、查询平均成绩大于85的所有学生的学号、姓名和平均成绩

    select t1.sname, t2.sid ,avg(t2.grade ) from t_student t1, t_score t2

    where t1.sid=t2.sid group by t2.sid,t1.sname

    having avg(t2.grade )>85;

    34、查询课程名称为“数据库”,且分数低于60的学生姓名和分数

    Select t1.sname,isnull(t2.grade ,0) from t_student t1, t_score t2,t_course t3

    where t2.sid = t1.sid and t2.cid = t3.cid

    and ame="数据库"and t2.grade <60;

    35、查询所有学生的选课情况;

    SELECT t1.sid, t1.cid,t2.sname,ame FROM t_score t1,t_student t2,t_course t3

    where t1.sid = t2.sid and t1.cid = t3.cid ;

    36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;

    SELECT distinct t1.sid,t1.sname,t2.cid, t2.grade FROM t_student t1, t_score t2

    WHERE t2.grade >=70 AND t2.sid = t1.sid;

    37、查询不及格的课程,并按课程号从大到小排列

    select cid from t_score where grade < 60 order by cid ;

    38、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;

    select t1.sid,t2.sname from t_score t1,t_student t2

    where t1.sid = t2.sid and t1.grade > 80 and t1.cid = "003";

    39、求选了课程的学生人数

    select count(*) from t_score;

    40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩

    select t1.sname,t2.grade from t_student t1, t_score t2,t_course t3,t_teacher t4

    where t1.sid = t2.sid

    and t2.cid = t3.cid

    and t3.tid = t4.tid

    and t4.Tname = "叶平"

    and t2.grade = (select max(grade )from t_score where cid=t3.cid );

    41、查询各个课程及相应的选修人数

    select count(*) from t_score group by cid

    42、查询不同课程成绩相同的学生的学号、课程号、学生成绩

    select distinct t1.sid,t2.grade from t_score t1 , t_score t2

    where t1.grade = t2.grade and t1.cid <>t2.cid ;

    43、查询每门功成绩最好的前两名

    SELECT t1.sid as 学生ID,t1.cid as 课程ID,grade as 分数 FROM t_score t1

    WHERE grade IN (

    SELECT TOP 2 grade FROM t_score

    WHERE t1.cid = cid ORDER BY grade DESC

    )

    ORDER BY t1.cid;

    44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列

    select cid as 课程号,count(*) as 人数 from t_score

    group by cid

    order by count(*) desc,cid

    45、检索至少选修两门课程的学生学号

    select sid from t_score group by sid having count(*) > = 2

    46、查询全部学生都选修的课程的课程号和课程名

    select cid,cname from t_course where cid in (select cid from t_score group by cid)

    47、查询没学过“叶平”老师讲授的任一门课程的学生姓名

    select sname from t_student

    where sid not in (

    select sid from t_course t1,t_teacher t2, t_score t3

    where t1.tid = t2.tid

    and t3.cid =t 1.cid

    and t2.tname = "叶平"

    );

    48、查询两门以上不及格课程的同学的学号及其平均成绩

    select sid,avg(isnull(grade ,0)) from t_score

    where sid in (

    select sid from t_score

    where grade <60 group by sid having count(*)>2

    )

    group by sid;

    49、检索“004”课程分数小于60,按分数降序排列的同学学号

    select sid from t_score where cid="004"and grade <60 order by grade desc;

    50、删除“002”同学的“001”课程的成绩

    delete from t_score where sid="001"and cid = "001";

    • 时事博文
    • 文化时尚
    • 潮流娱乐
    • 科技
    • 游戏
    • 女人
    • 个性推荐